Question

Комплексные числа!!!
Нужно z2/z1
z2= -0,7-1,2i
z1= 3-4i

Answer 1

$z_{1}=3-4i\\\\z_{2}=-0,7-1,2i\\\\\\\dfrac{z_{2} }{z_{1} } =\dfrac{-0,7-1,2i}{3-4i}=\dfrac{(-0,7-1,2i)\cdot(3+4i)}{(3-4i)(3+4i)}=\\\\\\=\dfrac{-2,1-2,8i-3,6i-4,8i^{2} }{3^{2}-(4i)^{2}}=\dfrac{-2,1-6,4i-4,8\cdot(-1)}{9-16\cdot(-1)} =\\\\\\=\dfrac{2,7-6,4i}{25} =0,108-0,256i$