Question

помогите срочно пожалуйста​

Answer 1

Объяснение:

$4)\ \\(\frac{c}{4})^{20}*(\frac{c}{4})^*=(\frac{c}{4})* (\frac{c}{4})^{25} \\(\frac{c}{4})^{20}*(\frac{c}{4})^*=(\frac{c}{4})^{25+1} \\(\frac{c}{4})^{20}*(\frac{c}{4})^*=(\frac{c}{4})^{26} \\(\frac{c}{4})^*=(\frac{c}{4})^{26-20}\\(\frac{c}{4})^*=(\frac{c}{4})^{6}\\\ *=6.$

$6)\\(\frac{2}{5}y)^6*(\frac{2}{5}y)^*=(\frac{2}{5}y)*(\frac{2}{5}y)^8\\(\frac{2}{5}y)^6*(\frac{2}{5}y)^*=(\frac{2}{5}y)^{8+1} \\(\frac{2}{5}y)^6*(\frac{2}{5}y)^*=(\frac{2}{5}y)^{9} \\ (\frac{2}{5}y)^*=(\frac{2}{5}y)^{9-6}\\ (\frac{2}{5}y)^*=(\frac{2}{5}y)^{3}\\\ *=3.$