Question

ПОМОГИТЕ ДАЮ 80 БАЛЛОВ
вычислите ​

Answer 1

$(2\sqrt{3})^{2}=4\cdot 3=\boxed{12}\\\\\sqrt{7}\cdot\sqrt{7}=(\sqrt{7} )^{2} =\boxed7\\\\2(\sqrt{12})^{2}+\sqrt{1} =2\cdot12+1=24+1=\boxed{25}\\\\(3\sqrt{2})^{2}=9\cdot 2=\boxed{18} \\\\\sqrt{3}\cdot\sqrt{3} =(\sqrt{3} )^{2}=\boxed3\\\\\sqrt{1}+2(\sqrt{11})^{2}=1+2\cdot 11=1+22=\boxed{23}$