Question

помогитееееееееееееееее с решением

Answer 1

$a-\dfrac{1}{a}=\dfrac{3}{4}\\\\\\\Big(a-\dfrac{1}{a}\Big)^{2} =\Big(\dfrac{3}{4} \Big)^{2} \\\\\\a^{2} -2\cdot a\cdot\dfrac{1}{a} +\dfrac{1}{a^{2} } =\dfrac{9}{16}\\\\\\a^{2}-2+\dfrac{1}{a^{2} }=\dfrac{9}{16}\\\\\\a^{2}+\dfrac{1}{a^{2} }=\dfrac{9}{16}+2\\\\\\\boxed{a^{2}+\dfrac{1}{a^{2} }=2\dfrac{9}{16}}$