Question

Вычислить значение функции
Y=-x³+2x²+1 при x=-2; 1; 0.5

Answer 1

при x = -2

$y = - {x}^{3} + 2 {x}^{2} + 1 = - {( - 2)}^{3} + 2 \times {( - 2)}^{2} + 1 = - ( - 8) + 2 \times 4 + 1 = 8 + 8 + 1 = 17$

при x = 1

$y = - {x}^{3} + 2 {x}^{2} + 1 = - {1}^{3} + 2 \times {1}^{2} + 1 = - 1 + 2 + 1 = 2$

при x = 0.5

$y = - {x}^{3} + 2 {x}^{2} + 1 = - {(0.5)}^{3} + 2 \times {(0.5)}^{2} + 1 = - 0.125 + 0.5 + 1 = 1.375$

Answer 2

Ответ:

$y=-x^3+2x^2+1\\\\x=-2:\ \ y(-2)=-(-2)^3+2\cdot (-2)^2+1=8+8+1=17\\\\x=1:\ \ y(1)=-1^3+2\cdot 1^2+1=-1+2+1=2\\\\x=0:\ \ y(0)=-0^3+2\cdot 0^2+1=0+0+1=1\\\\x=0,5:\ \ y(0,5)=-0,5^3+2\cdot 0,5^2+1=-0,125+0,5+1=1,375$