Question

Помогите пожалуйста​

Answer 1

Ответ:

Объяснение:

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Answer 2

Ответ:

$1)\ \ \displaystyle \frac{5a^2}{4c^2}=\frac{5a^2\cdot 3a}{12ac^2}=\frac{15a^3}{12ac^2}\\\\\frac{3a}{a+3c}=\frac{3a\cdot 2}{2(a+3c)}=\frac{6a}{2a+6c}\\\\\\\frac{5}{x+y}=\frac{5(x-y)}{(x+y)(x-y)}=\frac{5(x-y)}{x^2-y^2}\\\\\\2)\ \ \frac{16x^2}{8x^2y}=\frac{8x^2\cdot 2}{8x^2\cdot y} =\frac{2}{y}\\\\\\\frac{mx-my}{p(x-y)}=\frac{m(x-y)}{p(x-y)}=\frac{m}{p}$