Question

$\frac{x - 1}{3} + \frac{y - 1}{2 } = 2$
$\frac{x - 1}{2 } - \frac{y - 1}{12} = \frac{3}{4}$
помагите решить систему срочно​

Answer 1

$\displaystyle\left \{ {{\dfrac{x-1}{3}+\dfrac{y-1}{2}=2 } \atop {\dfrac{x-1}{2}-\dfrac{y-1}{12}=\dfrac{3}{4}}} \right.\\\\\\\displaystyle\left \{ {{\dfrac{x-1}{3}\cdot6+\dfrac{y-1}{2}\cdot6=2\cdot6 } \atop {\dfrac{x-1}{2}\cdot12-\dfrac{y-1}{12}\cdot12=\dfrac{3}{4}}\cdot12} \right.\\\\\\\displaystyle\left \{ {{2\cdot(x-1)+3\cdot(y-1)}=12 \atop {6\cdot(x-1)-(y-1)=9}} \right. \\\\\\\displaystyle\left \{ {{2x-2+3y-3}=12 \atop {6x-6-y+1=9}} \right.$

$\displaystyle\left \{ {{2x+3y=17} \atop {6x-y=14} \ |\cdot3} \right. \\\\\\+\displaystyle\left \{ {{2x+3y=17} \atop {18x-3y=42}} \right. \\---------\\20x=59\\\\x=2,95\\\\y=6x-14=6\cdot2,95-14=17,7-14=3,7\\\\Otvet:\boxed{(2,95 \ ; \ 3,7)}$