Question

решите систему неравенств.

Answer 1

$\left \{ {{4(x+1)\leq 9-2x} \atop {2(x+5)\leq1-x }} \right. \\\\\left \{ {{4x+4\leq 9-2x} \atop {2x+10\leq1-x }} \right. \\\\\left \{ {{4x+2x\leq 9-4} \atop {2x+x\leq1-10 }} \right.\\\\\left \{ {{6x\leq5 } \atop {3x\leq-9 }} \right. \\\\\left \{ {{x\leq \frac{5}{6} } \atop {x\leq-3 }} \right. \ \Rightarrow \ x\leq -3\\\\Otvet:\boxed{x\in(-\infty \ ; \ -3]}$

Answer 2

Объяснение:

{4(х+1)<=9-2х

{2(х+5)<=1-х

4х+4<=9-2х

2х+10<=1-х

4х+2х<=9-4

2х+х<=1-10

6х<=5

3х<= - 9

Х<=5/6

Х<= - 3

Ответ х€(-бесконечности ; - 3]