Question

(2x - 1)^2 - 4x - 13 = 0
через дискриминант
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Answer 1

Ответ:

$(2x - 1) {}^{2} - 4x - 13 = 0 \\ 4 {x}^{2} - 2x + 1 - 4x - 13 = 0 \\ {4x}^{2} - 6x - 12 = 0 \\ {x}^{2} - 1.5x - 3 = 0 \\ d = b {}^{2} - 4ac \\ d = 2 \frac{1}{4} + 4 \times 3 \\ d = 14 \frac{1}{4 } \\ x1 = \frac{3 - \sqrt{57} }{4 } \\ x2 = \frac{3 + \sqrt{57} }{4}$