Question

X^2+12x+7=0
Помогите пожалуйста

Answer 1

$x^2+12x+7=0\\\\D=b^2-4ac=12^2-4*1*7=144-28=116\\\\x_1=\frac{-b+\sqrt{D} }{2a}=\frac{-12+\sqrt{116} }{2*1}=\frac{-12+2\sqrt{29} }{2}=-12+\sqrt{29}\\\\x_2=\frac{-b-\sqrt{D} }{2a}=\frac{-12-\sqrt{116} }{2*1}=\frac{-12-2\sqrt{29} }{2}=-12-\sqrt{29}$

Ответ:  x₁ = -12 + √29   x₂= -12 - √29

Answer 2

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