Question

помогите пж!!!!!!!!!!!​

Answer 1

Ответ:

$1)\ \ a=-4\ ,\ \ \dfrac{a^2-1}{a-5}=\dfrac{(a-1)(a+1)}{a-5}=\dfrac{(-4-1)(-4+1)}{-4-5}=\\\\\\=\dfrac{-5\cdot (-3)}{-9}=-\dfrac{5}{3}=-1\dfrac{2}{3}\\\\\\2)\ \ x=-5\ ,\ y=6\ ,\ \ \ \dfrac{x+3}{y}-\dfrac{y}{x+2}=\dfrac{-5+3}{6}-\dfrac{6}{-5+2}=\dfrac{-2}{6}-\dfrac{6}{-3}=\\\\\\=-\dfrac{1}{3}+2=1\dfrac{2}{3}$