Question

|х+7|=4 решение пжпжпж...............

Answer 1

|х+7|=4

х+7=4

х+7=-4

х=-3

х=-11

Ответ: х¹=-3, х²=-11

Answer 2

$|x + 7| = 4 \\ x + 7 = 4 \\ x = 4 - 7\\ x {}^{1} = - 3 \\ \\ |x + 7| = 4 \\ x + 7 = - 4 \\ x = - 4 - 7 \\ x {}^{2} = - 11$