Question

Помогите решить дам 30 балов​

Answer 1

Пошаговое объяснение:

$1)3 {x}^{2} + 13x - 10 = 0 \\ d = 169 + 120 = 289 \\ \sqrt{d} = \sqrt{289} = 17 \\ x1 = \frac{ - 13 - 17}{6} = - \frac{30}{6} = - 5 \\ x2 = \frac{ - 13 + 17}{6} = \frac{4}{6} = \frac{2}{3}$

$2)49 - 16 {x}^{2} = 0 \\ (7 - 4x) (7 + 4x)= 0 \\7 - 4x = 0 \\ 4x = 7 \\ x = \frac{7}{4} \\ x = 1.75 \\ 7 + 4x = 0 \\ 4x = - 7 \\ x = - \frac{7}{4} \\ x = - 1.75 \\ or \\ 49 - 16 {x}^{2} = 0 \\ d = 16 \times 49 \times 4 = 3136 \\ \sqrt{d} = \sqrt{3136} = 56 \\ x1 = \frac{56}{32} = \frac{7}{4} = 1.75 \\ x2 = - \frac{56}{32} = - \frac{7}{4} = - 1.75$

${x}^{2} - 27 = 0 \\ (x - 3 \sqrt{3} )(x + 3 \sqrt{3} ) = 0 \\ x - 3 \sqrt{3} = 0 \\ x = 3 \sqrt{3} \\ x + 3 \sqrt{3} = 0 \\ x = - 3 \sqrt{3} \\ or \\ {x}^{2} - 27 = 0 \\ d = 27 \times 4 = 108 \\ \sqrt{d} = \sqrt{108} = 6 \sqrt{3} \\ x1 = \frac{6 \sqrt{3} }{2} = 3 \sqrt{3} \\ x2 = - \frac{6 \sqrt{3} }{2} = - 3 \sqrt{3}$