Question

cos45⁰-tg45⁰-sin135⁰-ctg135⁰​

Answer 1

Ответ:

0

Объяснение:

$\displaystyle cos45^{o}-tg45^{o}-sin135^{o}-ctg135^{o}=\frac{\sqrt{2} }{2}-1-sin(90^{o}+45^{o})-ctg(90^{o}+45^{o})=\frac{\sqrt{2} }{2}-1 -(-cos(45^{o}))-(-tg(45^{o}))=\frac{\sqrt{2} }{2}-1+\frac{\sqrt{2} }{2}+1=0$