Question

пжжж помагите 11.
пжжж помагите 11.​

Answer 1

Объяснение:

1)

$6\frac{3}{7} a-8\frac{5}{8}b-\frac{2}{3}c=\frac{45}{7}*\frac{14}{15} +\frac{69}{8}*2\frac{18}{23}+\frac{2}{3} *(-6,75)=6+\frac{69}{8}*\frac{64}{23} -\frac{2}{3} *6\frac{3}{4}=\\=6+24-\frac{2}{3}*\frac{27}{4} =30-4,5=25,5.$

2)

$2\frac{4}{11} a-19,25b+\frac{4}{9}c=\frac{26}{11}*13,2-19\frac{1}{4}*2\frac{10}{11}+\frac{4}{9}*(-10\frac{1}{8})=\\=\frac{26}{11}*13\frac{1}{5}-\frac{77}{4}*\frac{32}{11}-\frac{4}{9}*\frac{81}{8}=\frac{26}{11}*\frac{66}{5}-56-\frac{9}{2} =\frac{156}{5}-56-4,5= 31,2-51,5=-20,3$

3)

$36\frac{2}{3} a-4,84b+7\frac{5}{7} c=\frac{110}{3} *0,9-4\frac{21}{25}*3\frac{9}{22}+\frac{54}{7}*3,5=\frac{110}{3}*\frac{9}{10} -\frac{121}{25}*\frac{75}{22}+\frac{54}{7}*\frac{7}{2}= \\=33-\frac{33}{2} +27=60-16,5=43,5.$

4)

$53\frac{7}{9}a-8,2b+4\frac{17}{38}c=\frac{484}{9}*3\frac{15}{22} -8\frac{1}{5}*(-\frac{25}{82})+\frac{169}{38}*(-4\frac{5}{13})=\\=\frac{484}{9}*\frac{81}{22} +\frac{41}{5}*\frac{25}{82} -\frac{169}{38}*\frac{57}{13} =198+\frac{5}{2} -\frac{39}{2}=198-\frac{34}{2}=198-17=181.$