Question

можно с решением помогите пожалуйста​

Answer 1

Пошаговое объяснение:

1).

$\frac{2}{43} \times 10 \frac{3}{4} = \frac{2}{43} \times \frac{43}{4} = \frac{1}{2}$

$5 \frac{1}{7} \div 2 \frac{4}{7} = \frac{36}{7} \div \frac{18}{7} = \frac{36}{7} \times \frac{7}{18} = 2$

$\frac{2}{43} \times 10 \frac{3}{4} < 5 \frac{1}{7} \div 2 \frac{4}{7}$

2).

$5 \frac{2}{3} \times \frac{9}{34} = \frac{17}{3} \times \frac{9}{34} = \frac{3}{2} = 1.5$

$11 \frac{1}{2} \div 8 \frac{5}{8} = \frac{23}{2} \div \frac{69}{8} = \frac{23}{2} \times \frac{8}{69} = \frac{4}{3}$

$5 \frac{2}{3} \times \frac{9}{34} > 11 \frac{1}{2} \div 8 \frac{5}{8}$

3).

$9 \frac{1}{2} \times \frac{1}{19} = \frac{19}{2} \times \frac{1}{19} = \frac{1}{2}$

$3 \frac{1}{6} \div 6 \frac{1}{3} = \frac{19}{6} \div \frac{19}{3} = \frac{19}{6} \times \frac{3}{19} = \frac{1}{2}$

$9 \frac{1}{2} \times \frac{1}{19} = 3 \frac{1}{6} \div 6 \frac{1}{3}$

4).

$\frac{8}{15} \times \frac{20}{24} = \frac{4}{3 \times 3} = \frac{4}{9}$

$1 \frac{8}{27} \div 1 \frac{2}{3} = \frac{35}{27} \div \frac{5}{3} = \frac{35}{27} \times \frac{3}{5} = \frac{7}{9}$

$\frac{8}{15} \times \frac{20}{24} < 1 \frac{8}{27} \div 1 \frac{2}{3}$