Question

сделай задание..........​

Answer 1

Объяснение:

я написала з поясненням

Answer 2

Ответ:

Объяснение:

1) $\frac{3+\sqrt{3}}{\sqrt{3}} = \frac{3+\sqrt{3}}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{(3+\sqrt{3})*\sqrt{3}}{(\sqrt{3})^2} = \frac{3\sqrt{3}+(\sqrt{3})^2}{3} = \frac{3\sqrt{3}+3}{3} = \frac{3*(\sqrt{3}+1)}{3} = \sqrt{3}+1$

2) $\frac{2\sqrt{3}-3}{4\sqrt{3}} = \frac{2\sqrt{3}-3}{4\sqrt{3}} * \frac{4\sqrt{3}}{4\sqrt{3}} = \frac{(2\sqrt{3}-3)*4\sqrt{3}}{(4\sqrt{3})^2} = \frac{2\sqrt{3}*4\sqrt{3}-3*4\sqrt{3}}{16*3} = \frac{8*3-12\sqrt{3}}{48} = \frac{24-12\sqrt{3}}{48} = \frac{12(2-\sqrt{3})}{12*4} = \frac{2-\sqrt{3}}{4}$

3) $\frac{2-3\sqrt{6}}{\sqrt{6}} = \frac{2-3\sqrt{6}}{\sqrt{6}} * \frac{\sqrt{6}}{\sqrt{6}} = \frac{(2-3\sqrt{6})*\sqrt{6}}{(\sqrt{6})^2} = \frac{2\sqrt{6}-3(\sqrt{6})^2}{6} = \frac{2\sqrt{6}-3*6}{6} = \frac{2\sqrt{6}-18}{6} = \frac{2(\sqrt{6}-9)}{2*3} = \frac{\sqrt{6}-9}{3}$