Question

Здравствуйте,помогите решить эти примеры пожалуйста подробно если можно​

Answer 1

Объяснение:

$1) \frac{ {3}^{2} \times {4}^{3} \times {12}^{2} }{ {9}^{2} \times {6}^{3} } = \frac{ {3}^{2} \times {( {2}^{2} )}^{3} \times {4}^{2} \times {3}^{2} }{ {( {3}^{2}) }^{2} \times {2}^{3} \times {3}^{3} } = \frac{ {3}^{4} \times {2}^{6} \times {2}^{4} }{ {3}^{4} \times {2}^{3} \times {3}^{3} } = \frac{ {3}^{4} \times {2}^{10} }{ {3}^{7} \times {2}^{3} } = \frac{ {2}^{7} }{ {3}^{3} } = \frac{128}{27} = 4 \frac{20}{27 } \\ \\ 2) \frac{ {5}^{2} \times {6}^{4} \times {12}^{2} }{ {15}^{2} \times {9}^{3} } = \frac{ {5}^{2} \times {3}^{4} \times {2}^{4} \times {3}^{2} \times {2}^{2} }{ {5}^{2} \times {3}^{2} \times {3}^{6} } = \frac{ {5}^{2} \times {3}^{6} \times {2}^{6} }{ {5}^{2} \times {3}^{8} } = \frac{ {2}^{6} }{ {3}^{2} } = \frac{64}{9} = 7 \frac{1}{9} \\ \\ 3) \frac{ {12}^{2} \times {4}^{3} \times {6}^{2} }{ {8}^{2} \times {18}^{3} } = \frac{ {3}^{2} \times {2}^{2} \times {2}^{6} \times {3}^{2} \times {2}^{2} }{ {2}^{5} \times {2}^{3} \times {3}^{6} } = \frac{ {3}^{4} \times {2}^{10} }{ {2}^{8} \times {3}^{6} } = \frac{ {2}^{2} }{ {3}^{2} } = \frac{4}{9} \\ \\ 4) \frac{ {( {3}^{3} )}^{3} \times {( {3}^{2}) }^{7} \times {2}^{2} }{ {( {3}^{4}) }^{5} \times {2}^{3} } = \frac{ {3}^{9} \times {3}^{14} \times {2 }^{2} }{ {3}^{20} \times {2}^{3} } = \frac{ {3}^{23} \times {2}^{2} }{ {3}^{20} \times {2}^{3} } = \frac{ {3}^{3} }{2} = \frac{27}{2} = 13.5$