Question

Помогите пожалуйста решить
$20 \div (6 \times \frac{3}{11} + 1 \times \frac{8}{11}) + (7 \times \frac{2}{5} + 5.8) \div 5$
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Answer 1

Пошаговое объяснение:

$20 \div (6 \times \frac{3}{11} + 1 \times \frac{8}{11}) + (7 \times \frac{2}{5} + 5.8) \div 5 = 20 \div ( \frac{18}{11} + \frac{8}{11} ) + ( \frac{37}{5} + 5.8) \div 5 = 20 \div \frac{26}{11} + 13.2 \div 5 = \frac{20 \times 11}{26} + 2.64 = \frac{110}{13} + 2 \frac{32}{50} = 8 \frac{6}{13} + 2 \frac{32}{50} = 10 \frac{300 + 416}{650} = 100 \frac{716}{650} = 11 \frac{66}{650} = 11 \frac{33}{325}$