Question

Можно пожалуйста по действиям​

Answer 1

Ответ:

$-66$

Пошаговое объяснение:

$1) \ 53\dfrac{3}{4}+9\dfrac{1}{6}=53\dfrac{9}{12}+9\dfrac{2}{12}=53+9+\dfrac{9}{12}+\dfrac{2}{12}=62+\dfrac{11}{12}=62\dfrac{11}{12} \ ;$

$2) \ 62\dfrac{11}{12} \cdot 1\dfrac{1}{5}=\dfrac{62 \cdot 12+11}{12} \cdot \dfrac{6}{5}=\dfrac{(620+124+11) \cdot 6}{6 \cdot 2 \cdot 5}=\dfrac{755}{2 \cdot 5}=\dfrac{151}{2} \ ;$

$3) \ -\bigg (10\dfrac{3}{10}-8\dfrac{1}{2} \bigg )=-(10,3-8,5)=-1,8=-1\dfrac{4}{5}=-\dfrac{9}{5} \ ;$

$4) \ -\dfrac{9}{5} \cdot \dfrac{5}{9}=-1 \ ;$

$5) \ \dfrac{151}{2}:(-1)=-\dfrac{151}{2} \ ;$

$6) \ 3\dfrac{3}{7}-6\dfrac{4}{5}=3\dfrac{15}{35}-6\dfrac{28}{35}=-\bigg (6\dfrac{28}{35}-3\dfrac{15}{35} \bigg )=-3\dfrac{13}{35} \ ;$

$7) \ -3\dfrac{13}{35} \cdot 5\dfrac{5}{6}=-\dfrac{118}{35} \cdot \dfrac{35}{6}=-\dfrac{118}{6}=-\dfrac{59}{3} \ ;$

$8) \ -3\dfrac{1}{6}+3\dfrac{2}{3}=3\dfrac{4}{6}-3\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2} \ ;$

$9) \ -\dfrac{59}{3}:\dfrac{1}{2}=-\dfrac{59}{3} \cdot 2=-\dfrac{59 \cdot 2}{3}=-\dfrac{118}{3} \ ;$

$10) \ -\dfrac{151}{2}-\bigg (-\dfrac{118}{3} \bigg )=-\dfrac{453}{6}+\dfrac{236}{6}=-\dfrac{453-236}{6}=-\dfrac{217}{6}=-36\dfrac{1}{6} \ ;$

$11) \ -36\dfrac{1}{6}+\bigg (-29\dfrac{5}{6} \bigg )=-36\dfrac{1}{6}-29\dfrac{5}{6}=-\bigg (36\dfrac{1}{6}+29\dfrac{5}{6} \bigg )=-(36+29+1)=$

$=-(36+30)=-66;$