Question

СРОЧНО!!!
Упростите :
15 БАЛЛОВ​

Answer 1

Ответ:

63

Пошаговое объяснение:

$\frac{ {21}^{4n + 3} }{ {3}^{4n + 1} {7}^{4n + 2} } = \frac{ { {7}^{4n} \times {7}^{3} \times {3}^{4n} \times 3 }^{3} }{{3}^{4n} \times 3 \times {7}^{4n} \times {7}^{2} } = \frac{ {7}^{3} \times {3}^{3} }{3 \times {7}^{2} } = 7 \times {3}^{2} = 63$

Answer 2

Ответ:

$\displaystyle \Large \boldsymbol{} 1) \ \ a^n \cdot b^n =(ab)^n \\\\ 2) \ \ \frac{a^n}{a^m}=a^{n-m} \\\\\\ \frac{21^{4n+3}} {3^{4n+1}\cdot 7^{4n+2}} = \frac{21^{4n+3}}{\underbrace{3^{4n+1}\cdot 7^{4n+1}}_{21^{4n+1}} \cdot 7}=21^{4n+3-4n-1}:7= \\\\\\ 21 \cdot 21:7=21\cdot3=\boxed{\boldsymbol{63}}$