Question

Задание на фотографии

Answer 1

Ответ:

$1)\ \ 2x^2-50=0\ \ ,\ \ \ x^2-25=0\ \ ,\ \ ,\ \ (x-5)(x+5)=0\\\\x_1=-5\ ,\ x_2=5\\\\\\2)\ \ x^2+10x=0\ \ ,\ \ \ x\, (x+10)=0\ \ ,\\\\x_1=0\ \ ,\ \ x_2=-10\\\\\\3)\ \ 6x^2-30=0\ \ ,\ \ x^2-5=0\ \ ,\ \ \ (x-\sqrt5)(x+\sqrt5)=0\ \ ,\\\\x_1=-\sqrt5\ \ ,\ \ x_2=\sqrt5\\\\\\4)\ \ 6x^2-42x=0\ \ ,\ \ \ 6x\, (x-7)=0\ \ ,\\\\x_1=0\ \ ,\ \ x_2=7$

Answer 2

$1) \ 2x^{2} -50=0 \ |:2\\\\x^{2} -25=0\\\\(x-5)(x+5)=0\\\\\left[\begin{array}{ccc}x-5=0\\x+5=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1}=5 \\x_{2}=-5 \end{array}\right\\\\\\2) \ x^{2} +10x=0\\\\x(x+10)=0\\\\\left[\begin{array}{ccc}x=0\\x+10=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1}=0 \\x_{2}=-10 \end{array}\right$

$3) \ 6x^{2}-30=0 | \ :6\\\\x^{2}-5=0\\\\(x-\sqrt{5})(x+\sqrt{5})=0\\\\\left[\begin{array}{ccc}x-\sqrt{5} =0\\x+\sqrt{5} =0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1}=\sqrt{5}\\x_{2}=-\sqrt{5}\end{array}\right\\\\\\4) \ 6x^{2}-42x=0 \ |:6\\\\x^{2}-7x=0\\\\x(x-7)=0\\\\\left[\begin{array}{ccc}x=0\\x-7=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1}=0 \\x_{2}=7 \end{array}\right$