Question

Помогите решить, пожалуйста!!!! Номер 1.12

Answer 1

$\frac{1}{1-b} + \frac{1}{1+b} = \frac{1 + b + 1 - b}{(1-b)(1+b)} = \frac{2}{1-b^2}\\\frac{2}{1-b^2} + \frac{2}{1+b^2} = \frac{2 + 2b^2 + 2 - 2b^2}{(1-b^2)(1+b^2)} = \frac{4}{1-b^4}\\...\\\frac{2^n}{1-b^{2^n}} + \frac{2^n}{1+b^{2^n}} = \frac{2^{(n+1)}}{1-b^{2^{(n+1)}}}$