Question

помогите срочно !!!!

Answer 1

√(3*√4) / ∛2 = √(3*2) / ∛2 = √6 / ∛2 = √3*√2 / ∛2 = √3*⁶√2

¹⁵√2 / ⁵√(∛ 2) = ¹⁵√2 / ¹⁵√2 = 1

√(∛81) / ∛9 = ⁶√ 3⁴ / ∛ 3² = ∛ 3² / ∛ 3² = 1

√(3*√4) / ∛2 + ¹⁵√2 / ⁵√(∛ 2) + √(∛81) / ∛9 = 2 + √6 / ∛2 = ⁶√2 * √3 + 2

Answer 2

Ответ:

$\displaystyle \frac{\sqrt{3\sqrt4}}{\sqrt[3]2}+\frac{\sqrt[15]{2}}{\sqrt[5]{\sqrt[3]{2}}}+\frac{\sqrt{\sqrt[3]{81}}}{\sqrt[3]{9}}=\frac{\sqrt{\sqrt{9\cdot 4}}}{\sqrt[3]2}+\frac{\sqrt[15]{2}}{\sqrt[15]{2}}+\frac{\sqrt[3]{\sqrt{81}}}{\sqrt[3]{9}}=\\\\\\=\frac{\sqrt{3\cdot 2}}{\sqrt[3]2}+1+\frac{\sqrt[3]{9}}{\sqrt[3]9}=\frac{\sqrt3\cdot \sqrt2}{\sqrt[3]2}+1+1=\dfrac{\sqrt3\cdot \sqrt[6]{2^3}}{\sqrt[6]{2^2}}+2=\\\\\\=\sqrt3\cdot \sqrt[6]{\frac{2^3}{2^2}}+2=\sqrt3\cdot \sqrt[6]2+2$