Question

А)х^6-у^8
Б)к^4-81
Разложить на множители
Заранее благодарю

Answer 1

$\boxed{ {a}^{2} - {b}^{2} = (a + b)(a - b) }$

${x}^{6} - {y}^{8} = {( {x}^{3}) }^{2} - {( {y}^{4} )}^{2} = \boldsymbol{ ( {x}^{3} + {y}^{4} )( {x}^{3} - {y}^{4} )}$

${k}^{4} - 81 = {( {k}^{2}) }^{2} - {9}^{2} = ( {k}^{2} + 9)( {k}^{2} - 9) = \boldsymbol{( {k}^{2} + 9)( k + 3)(k - 3)}$