Question

скоротити дріб. дуже треба!​

Answer 1

$\dfrac{5y+10}{y^{2}-2y-8 } =\dfrac{5(y+2)}{(y+2)(y-4)}=\boxed{\dfrac{5}{y-4}}$

$y^{2} -2y-8=0\\\\D=(-2)^{2} -4\cdot (-8)=4+32=36=6^{2}\\\\y_{1} =\dfrac{2-6}{2}=-2\\\\y_{2} =\dfrac{2+6}{2}=4\\\\y^{2} -2y-8=(y+2)(y-4)$