Question

Помогите с геометрией, задания на фото.

Answer 1

Ответ:

$4.1.\ \ \ \alpha =20^\circ \ ,\ \ \beta =60^\circ \ \ ,\\\\{}\ \ \ \ \ \alpha +\beta +\gamma =360^\circ \\\\{}\ \ \ \ \ \gamma =360^\circ -\alpha -\beta =360^\circ -20^\circ -60^\circ =280^\circ \\\\\\4.2.\ \ \ \beta =2\alpha \ ,\ \ \gamma=15\alpha \ \ ,\\\\{}\ \ \ \ \ \alpha +\beta +\gamma =360^\circ \\\\{}\ \ \ \ \ \alpha +2\alpha +15\alpha =360^\circ \ \ \to \ \ \ 18\alpha =360^\circ \ \ ,\ \ \alpha =20^\circ \ \ ,\\\\{}\ \ \ \ \ \gamma=15\cdot 20^\circ =300^\circ$