Question

срочно нужно решить плиз.​

Answer 1

Ответ:

Cократите дробь:

$1)\ \dfrac{y^2-16}{3y+12} = \dfrac{(y-4)(y+4)}{3(y+4)} = \dfrac{y-4}{3}.\\\\2)\ \dfrac{5x-15y}{x^2-9y^2} = \dfrac{5(x-3y)}{(x-3y)(x+3y)} = \dfrac{5}{x+3y}.\\\\3)\ \dfrac{(c+2)^2}{7c^2+14c} = \dfrac{(c+2)^2}{7c(c+2)}=\dfrac{c+2}{7c}.\\\\4)\ \dfrac{6cd-18c}{(d-3)^2} = \dfrac{6c(d-3)}{(d-3)^2} = \dfrac{6c}{d-3}.$

Упростите выражение:

$1)\ \dfrac{a-b}{b-a} = -\dfrac{a-b}{a-b}=-1.\\\\2)\ \dfrac{(a-b)^2}{(b-a)^2} = -\dfrac{(a-b)^2}{(a-b)^2} = -1.\\\\3)\ \dfrac{(a-b)^2}{b-a} =-\dfrac{(a-b)^2}{a-b} =-(a-b)=-a+b=b-a.\\\\4)\ \dfrac{a-b}{(b-a)^2} =-\dfrac{a-b}{(a-b)^2} = -\dfrac{1}{a-b} = \dfrac{1}{b-a}.$

Упростите выражение:

$1)\ \dfrac{x^2-10x+25}{3x+12}*\dfrac{x^2-16}{2x-10} =\dfrac{(x-5)^2}{3(x+4)}*\dfrac{(x-4)(x+4)}{2(x-5)}=\dfrac{x-5}{3}*\dfrac{x-4}{2} =\dfrac{(x-5)(x-4)}{6} = \dfrac{x^2-4x-5x+20}{6} =\dfrac{x^2-9x+20}{6}.\\\\2)\ \dfrac{1-a^2}{4a+8b}* \dfrac{a^2+4ab+4b^2}{3-3a} = \dfrac{(1-a)(1+a)}{4(a+2b)}*\dfrac{(a+2b)^2}{3(1-a)}=\dfrac{1+a}{4}*\dfrac{a+2b}{3} = \dfrac{(1+a)(a+2b)}{12} = \dfrac{a+2b+a^2+2ab}{12}.$