Question

АЛГЕБРААА СРОЧНО МОЛЮЮЮЮЮЮЮ

Answer 1

$1) \ \dfrac{5}{12}lk+\Big(-\dfrac{1}{6}lk\Big)+lk +\Big(4lk-\dfrac{1}{4}lk\Big)=\\\\=\dfrac{5}{12}lk-\dfrac{1}{6}lk+lk +4lk-\dfrac{1}{4}lk=\Big(\dfrac{5}{12}lk-\dfrac{1}{6}lk-\dfrac{1}{4}lk\Big)+lk+4lk=\\\\=\Big(\dfrac{5}{12}lk-\dfrac{2}{12}lk-\dfrac{3}{12}lk\Big)+5lk=0+5lk=\boxed{5lk}$

$2) \ 16a^{2}c^{5} \cdot\Big(-\dfrac{1}{4}a^{4}c\Big)=16\cdot \Big(-\dfrac{1}{4}\Big)\cdot a^{2+4} \cdot c^{5+1}=\boxed{-4a^{6} c^{6}}\\\\\\3) \ \Big(-3\dfrac{1}{2}ab^{2}\Big)^{2} = \Big(-\dfrac{7}{2}\Big)^{2}\cdot a^{2} \cdot \Big(b^{2} \Big)^{2} =\dfrac{49}{4} a^{2} b^{4}=\boxed{12,25a^{2}b^{4}}$