Question

помогите срочно пожалуйста
$x {}^{2} + 17 = 9x + 4 |x - 3|$
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Answer 1

Смотри вложение ....

Answer 2

$x^{2} +17=9x+4|x-3|\\\\1) \ x<3\\\\x^{2} +17=9x+4(3-x)\\\\x^{2} +17=9x+12-4x\\\\x^{2}-5x+5=0\\\\D=(-5)^{2}-4\cdot 5=25-20=5\\\\x_{1}=\dfrac{5-\sqrt{5} }{2}\\\\x_{2}=\dfrac{5+\sqrt{5} }{2}>3-neyd$

$2)x\geq3\\\\x^{2} +17=9x+4(x-3)\\\\x^{2} +17=9x+4x-12\\\\x^{2} -13x+29=0\\\\D=(-13)^{2} -4\cdot 29=169-116=53\\\\x_{1}=\dfrac{13-\sqrt{53} }{2} <3-neyd\\\\x_{2} =\dfrac{13+\sqrt{53} }{2}\\\\Otvet:\boxed{\dfrac{5-\sqrt{5} }{2} \ ; \ \dfrac{13+\sqrt{53} }{2} }$