Question

Помогите срочно
$|x - 2| x {}^{2} = 10 - 5x$
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Answer 1

$|x-2|x^{2}=10-5x\\\\1) \ x<2\\\\(2-x)x^{2} =10-5x\\\\2x^{2}-x^{3} -10+5x=0\\\\x^{3}-2x^{2} -5x+10=0\\\\(x^{3}-2x^{2}) -(5x-10)=0\\\\x^{2} (x-2)-5(x-2)=0\\\\(x-2)(x^{2} -5)=0\\\\\\\left[\begin{array}{ccc}x-2=0\\x^{2}-5=0 \end{array}\right\\\\\\\left[\begin{array}{ccc}x=2-neyd\\x^{2}=5 \end{array}\right\\\\x^{2} =5\\\\\left[\begin{array}{ccc}x_{1}=-\sqrt{5} \\x_{2}=\sqrt{5}>2-neyd \end{array}\right \\\\\boxed{x=-\sqrt{5} }$

$2) \ x\geq2\\\\(x-2)x^{2}=10-5x\\\\x^{3} -2x^{2}+5x-10=0\\\\(x^{3} -2x^{2})+(5x-10)=0\\\\x^{2}(x-2)+5(x-2)=0\\\\(x-2)(x^{2}+5)=0\\\\\\\left[\begin{array}{ccc}x-2=0\\x^{2}+5=0 \end{array}\right\\\\\\\left[\begin{array}{ccc}x=2\\x^{2}=-5-kornei \ net \end{array}\right\\\\\boxed{x=2}\\\\Otvet:\boxed{-\sqrt{5} \ ; \ 2}$

Answer 2

Смотри вложение ....