Question

пожалуйста можна полное решение ​

Answer 1

Ответ:

$\left\{\begin{array}{l}5x-2y=-1\ |\cdot 2\\3x+4y=1\end{array}\right\ \ \oplus \ \left\{\begin{array}{l}13x=-1\\3x+4y=1\end{array}\right\ \ \left\{\begin{array}{l}x=-\dfrac{1}{13}\\4y=1-3x\end{array}\right\\\\\\\left\{\begin{array}{l}x=-\dfrac{1}{13}\\4y=1+\dfrac{3}{13}\end{array}\right\ \ \left\{\begin{array}{l}x=-\dfrac{1}{13}\\4y=\dfrac{16}{13}\end{array}\right\ \ \left\{\begin{array}{l}x=-\dfrac{1}{13}\\y=\dfrac{4}{13}\end{array}\right\ \ \ Otvet:\ \ \Big(\, -\dfrac{1}{13}\ ;\ \dfrac{4}{13}\Big)\ .$

Answer 2

Ответ: $\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppppppppppppppppppppppppp\ddddddddddddddddddd\huge \boxed{ x=-\frac{1}{13} \ \ ; \ \ y=\frac{4}{13} }$

Объяснение:

$\displaystyle\ \Large \boldsymbol{} + \left \{ {{5x-2y=-1 \ |\times 2} \atop {\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!3x+4y=1}} \right. => \\\\\\\\10x+3x+4y\!\!\!\!\diagup-4y\!\!\!\!\diagup=-2+1 \\\\\\ 13x=-1 \\\\\\x=-\frac{1}{13} \ \ ; \ \ y=\frac{-1-5x}{-2} =\frac{4}{13}$