Question

Срочно! Нужна помощь с логарифмами!

Answer 1

log(a) b = 1/ log(b) a

log(a^l) b^k = k/l log(a) b

log(a) x + log(a) y = log(a) xy

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10

log(6) mn = 7

log(6) 9m + log(6) 4n = log(6) 36mn = log(6) 6² + log(6) mn = 2 + 7 = 9

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11

log(2) 3 = a

log(2) 5 = b

log(2) 135 = log(2) 3³*5 = log(2) 3³ + log(2) 5 = 3 log(2) 3 + log(2) 3 = 3a + b

135 = 3*3*3*5 = 3³ * 5

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12

log(30) 3 = a

log(30) 5 = b

log(30) 8 = log(30) 2³ = 3*log(30) 2 = 3*log(30) 30/15 = 3*(log(30) 30 - log(30) 15 ) = 3*(1 - log(30) 3*5) = 3*(1 - log(30) 3 - log(30) 5) = 3*(1 - a - b)