Question

розв'язати систему нерівностей​

Answer 1

$\left\{\begin{array}{ccc}x^{2}-5x+6\geq 0 \\2x-5<0\end{array}\right\\\\\\\left\{\begin{array}{ccc}(x-2)(x-3)\geq 0 \\x<2,5\end{array}\right \\\\\\\left\{\begin{array}{ccc}x\in(-\infty \ ; \ 2] \ \cup \ [3 \ ; \ +\infty)\\x<2,5\end{array}\right$

+++++[2]------------[3]+++++

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_________₀__________

                  2,5

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Ответ : x ∈ ( - ∞ ; 2]