Question

МОЛЮ ПЖ АЛГЕБРУ ПРОШУУУУУУУ

Answer 1

Ответ:

1) 125.

2) -2/5.

3)  7.

4)  xu.

Объяснение:

1)  6⁴*9²/12⁵  : (3/20)³=2⁴*3⁴*3²*3²/3⁵*2⁵*2⁵ : 3³/2³*2³*5³=

=2⁴*3⁸/3⁵*2¹⁰ : 3³/2⁶*5³ = 3³/2⁶ *2⁶*5³/3³=5³=125.

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2)  (5/2)³ : (-125/8)*(5/2)⁰*2/5= (5/2)³ : (-5/2)³*1*2/5=-2/5.

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3)  m+n=?  если

a)  2^m=16;  =>  2^m=2^4 =>  m=4;

б) 3^n=27 => 3^n=3^3 => n=3;

m+n=4+3=7.

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4) x¹⁶*x⁴/x¹⁹ * u⁵⁶*u⁹/u⁶⁴=x²⁰⁻¹⁹ * u⁶⁵⁻⁶⁴=xu.

Answer 2

Ответ:

$1)\ 125;\\2)\ -\dfrac{2}{5};\\3)\ 7;\\4)\ x * u.$

Объяснение:

$1) \dfrac{6^4*9^2}{12^5} : (\dfrac{3}{20})^3 = \dfrac{6^4*9^2}{12^5} * \dfrac{20^3}{3^3} = \dfrac{3^4*2^4*3^4}{3^5*4^5} * \dfrac{4^3*5^3}{3^3} = \dfrac{2^4*3^4}{3*4^5} * \dfrac{4^3*5^3}{3^3} = \dfrac{2^4*3^3}{4^5} * \dfrac{4^3*5^3}{3^3} = \dfrac{2^4}{4^2} * \dfrac{5^3}{1} = \dfrac{2^4}{2^4} * \dfrac{5^3}{1} = 5^3 = 125.$

$2)\ (\dfrac{5}{2})^3 : (-\dfrac{125}{8}) * (\dfrac{5}{2})^{0} * \dfrac{2}{5} =-\dfrac{2}{5}. \\\\1) (\dfrac{5}{2})^3 : (-\dfrac{125}{8}) = \dfrac{125}{8} * (-\dfrac{8}{125}) = -1;\\\\2) -1 * (\dfrac{5}{2})^0 = -1 * 1 = -1;\\\\3) -1 * \dfrac{2}{5} = -\dfrac{2}{5}.$

$3)\ \\2^m = 16\\2^m = 2^4\\m =4;\\\\3^n = 27\\3^n = 3^3\\n = 3.\\\\m + n = 4 + 3 = 7.$

$4)\ \dfrac{x^{16} * x^4}{x^{19}} * \dfrac{u^{56} * u^{9}}{u^{64}} = \dfrac{x^{20}}{x^{19}} * \dfrac{u^{65}}{u^{64}} = x * u.$