Question

Решите систему неравенств

Answer 1

$\left\{\begin{array}{ccc}2x-\dfrac{2x-4}{3}>4 \\\dfrac{x}{2}-\dfrac{x}{8}\leq 12 \end{array}\right\\\\\\\left\{\begin{array}{ccc}2x\cdot 3-\dfrac{2x-4}{3}\cdot 3>4\cdot 3 \\\dfrac{x}{2}\cdot 8-\dfrac{x}{8}\cdot 8\leq 12\cdot 8 \end{array}\right\\\\\\\left\{\begin{array}{ccc}6x-2x+4>12\\4x-x\leq 96\end{array}\right \\\\\\\left\{\begin{array}{ccc}4x>8\\3x\leq 96\end{array}\right\\\\\\\left\{\begin{array}{ccc}x>2\\x\leq 32\end{array}\right\\\\\\Otvet:\boxed{x\in\Big(2 \ ; \ 32\Big]}$