Question

СРОЧНО ПОМОГИТЕ!!!!!!

Answer 1

Ответ: x ∈ [-6;-2]

Запишем систему уравнений:

$\left \{ {{4x+3\leq \frac{3x-4}{2} \ \ *2 \atop {\frac{3x-4}{2}\leq 2x+1}\ \ *2} \\\right.\\ \\ \\\left \{ {{8x+6\leq 3x-4 \atop {3x-4\leq 4x+2}} \right. \\ \\ \\\left \{ {{5x\leq -10 \atop {-x\leq 6}} \right. \\ \\ \\\left \{ {{x\leq -2 \atop {x\geq -6}} \right. \\ \\ \\\\-6\leq x\leq -2$

Answer 2

Ответ:

$4x+3\leq \dfrac{3x-4}{2}\leq 2x+1\ \ \Big|\cdot 2\\\\\\8x+6\leq 3x-4\leq 4x+2\ \ \Big|+4\\\\8x+10\leq 3x\leq 4x+6\\\\\\\left\{\begin{array}{l}3x\leq 4x+6\\3x\geq 8x+10\end{array}\right\ \ \left\{\begin{array}{l}3x-4x\leq 6\\3x-8x\geq 10\end{array}\right\ \ \left\{\begin{array}{l}-x\leq 6\\-5x\geq 10\end{array}\right\ \ \left\{\begin{array}{l}x\geq -6\\x\leq -2\end{array}\right\ \ \Rightarrow \\\\\\-6\leq x\leq -2\ \ \ \Rightarrow \ \ \ \ x\in [-6\ ;-2\ ]$