Question

ОТВЕТ НЕ 9
ПОМОГИТЕ ​

Answer 1

Ответ:13/6

Объяснение:

$\dfrac{x+y}{x-y}+\dfrac{x-y}{x+y}=3$

$\dfrac{(x+y)^2+(x-y)^2}{(x-y)(x+y)}=3$

$\dfrac{2(x^2+y^2)}{x^2-y^2}=3$

$\dfrac{x^2+y^2}{x^2-y^2}=\dfrac32$

$\dfrac{x^2+y^2}{x^2-y^2}+\dfrac{x^2-y^2}{x^2+y^2}=\dfrac{x^2+y^2}{x^2-y^2}+\dfrac{1}{\frac{x^2+y^2}{x^2-y^2}}=\dfrac32+\dfrac{1}{\frac32}=\dfrac32+\dfrac23=\dfrac{13}{6}$