Question

задание с дробными и десятичными степенями ​

Answer 1

Ответ:

$y\ne 0\ \ ,\ \ \dfrac{(16y)^{\frac{3}{2}}\cdot y^{3,6}}{y^{5,1}}=\dfrac{(2^4)^{\frac{3}{2}}\cdot y^{\frac{3}{2}}\cdot y^{\frac{18}{5}}}{y^{\frac{51}{10}}}=\dfrac{2^6\cdot y^{\frac{51}{10}}}{y^{\frac{51}{10}}}=2^6=64\\\\\\\\\star \ \ \dfrac{3}{2}+\dfrac{18}{5}=\dfrac{3\cdot 5+18\cdot 2}{10}=\dfrac{15+36}{10}=\dfrac{51}{10}\ \ \star$

Answer 2

$\dfrac{(16y)^{3/2} \cdot y^{3.6}}{y^{5.1}} = (16y)^{3/2} \cdot y^{3.6} \cdot y^{-5.1} = (2^4)^{3/2} \cdot y^{3/2} \cdot y^{3.6} \cdot y^{-5.1} = 2^{4 \cdot 3/2} \cdot y^{3/2 + 3.6 - 5.1} = 2^6 \cdot y^{3/2 - 1.5} = 64 \cdot y^0 = 64$