Question

2-log4(x+3)=log 4(x+3)​

Answer 1

Объяснение:

$2 - log_{4}(x + 3) = log_{4}(x + 3) \\ log_{4}(4 {}^{2} ) - log_{4}(x + 3) = log_{4}(x + 3) \\ log_{4}( \frac{4 {}^{2} }{x + 3} ) = log_{4}(x + 3) \\ log_{4}( \frac{16}{x + 3} ) = log_{4}(x + 3) \\ \frac{16}{x + 3} = x + 3 \\ 16 = ( x + 3) \times (x + 3) \\ 16 = (x + 3) {}^{2} \\ (x + 3) {}^{2} = 16 \\ x + 3 = ±4 \\ x + 3 = - 4 \\ x + 3 = 4 \\ x = - 7 \\ x = 1$