Question

Найдите sina,если cosa=0,6

Answer 1

$\displaystytle\bf \boxed{sin^2\alpha +cos^2\alpha =1} =>sin\alpha =\pm\sqrt{1-cos^2\alpha } \\\\sin\alpha =\pm\sqrt{1-0,6^2} =\pm0,8\\\\Otvet:sin\alpha=\pm0,8$