Question

1/2 * (1/2) ^2x-1 - (1/2)^x-1 > 0

Answer 1

Ответ:

$\in(-\infty;-1)$

Пошаговое объяснение:

$\frac{1}{2}*(\frac{1}{2})^{2x-1}-(\frac{1}{2})^{x-1}>0\\\\(\frac{1}{2})^{1+2x-1}>(\frac{1}{2})^{x-1}\\\\(\frac{1}{2})^{2x}>(\frac{1}{2})^{x-1}\\\\0<\frac{1}{2}<1\\\\2x<x-1\\\\2x-x<-1\\\\x<-1\\\\x\in(-\infty;-1)$