Предмет: Математика, автор: samprp3008

В какой момент времени скорость тела, движущегося по закону S(t)=t^(2) - 10t +38, равна 0? Найти ускорение тела.

Ответы

Автор ответа: afet74

0

Ответ:

Пошаговое объяснение:

S(t)=t²- 10t +38,

v=S‘(t)= 2t-10

2t-10=0

2t=10

t=10:2=5

t=5

при t=5. v=0

a=?

a=S''(t)=2

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