Question

ПОМОГИТЕ СРОЧНО!!!!ДАЮ 35 БАЛЛОВ!!!

Answer 1

Ответ:

Пошаговое объяснение:

1) -3∛⅓ = -3 * (∛1*3²/3*3²) = -3/3 ∛9= - ∛9

2)⁻⁵√⅖ = ⁻⁵√2*5⁴/5*5⁴ = (⁻⁵√1250) / 5

3) -2/3 (√27/2) = -2/3* (√27*2/2*2) =-2/3 * 1/2√54 = -1/3*√9*6 = -√6

4) -3/4*√32/3 = -3/4 *(√32*3/3*3) = -3/4 * 1/3√96 = -1/4 * √16*6 = -√6

5) -0,25√80=-0,25√5*16= - 0,25*4√5= - √5

6) -0,75√32= -0,75 *√16*2 = -0,75*4√2= - 3√2

Answer 2

$1)\;-3 \sqrt{\dfrac{1}{3}}=-\sqrt{9} \sqrt{\dfrac{1}{3}}= -\sqrt{9\cdot\dfrac{1}{3}}= -\sqrt{3}$

$2)\;-5 \sqrt{\dfrac{2}{5}}=-\sqrt{25} \sqrt{\dfrac{2}{5}}= -\sqrt{25\cdot\dfrac{2}{5}}= -\sqrt{10}$

$3)\;-\dfrac{2}{3} \sqrt{\dfrac{27}{2}}=-\sqrt{\dfrac{4}{9} } \sqrt{\dfrac{27}{2}}= -\sqrt{\dfrac{4}{9} \cdot\dfrac{27}{2}}= -\sqrt{2\cdot3}=-\sqrt{6}$

$4)\;-\dfrac{3}{4} \sqrt{\dfrac{32}{3}}=-\sqrt{\dfrac{9}{16}} \sqrt{\dfrac{32}{3}}= -\sqrt{\dfrac{9}{16} \cdot\dfrac{32}{3}}= -\sqrt{3\cdot2}=-\sqrt{6}$

$5)\;-0,25\sqrt{80}= -\dfrac{1}{4} \sqrt{16\cdot5}=-\dfrac{1}{4} \sqrt{16}\sqrt{5} =-\dfrac{1}{4}\cdot 4\sqrt{5} =-\sqrt{5}$

$6)\;-0,75\sqrt{32}= -\dfrac{3}{4} \sqrt{16\cdot2}=- \dfrac{3}{4}\sqrt{16}\sqrt{2}= - \dfrac{3}{4}\cdot4\sqrt{2}=-3\sqrt{2}$