Question

решите уравнение
$sin^{2} - sin \: x - 2 = 0$
​

Answer 1

Ответ:

$\sin {}^{2} (x) - \sin(x) - 2 = 0 \\ \\ \sin(x) = t \\ \\ t {}^{2} - t - 2 = 0\\ D= 1 + 8 = 9 \\ t_1 = \frac{1 + 3}{2} = 2 \\ t_2 = - 1 \\ \\ \sin(x) = 2$

нет корней

$\sin(x) = - 1 \\ x = - \frac{\pi}{2} + 2 \pi \: n, \\ n\in \: Z$