Question

оч нужна помощь с алгеброй2

Answer 1

Объяснение:

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Answer 2

Ответ:

$y=\sqrt{3-2x}+\dfrac{x^2-1}{\sqrt{x-1}}\\\\\\OOF:\ \ \left\{\begin{array}{l}3-2x\geq 0\\x-1>0\end{array}\right\ \ \left\{\begin{array}{l}-2x\geq -3\\x>1\end{array}\right\ \ \left\{\begin{array}{l}x\leq 1,5\\x>1\end{array}\right\ \ \ 1<x\leq 1,5\\\\\\\underline{\ x\in (\ 1\ ;\ 1,5\ ]\ }$