Question

X7.
Find area enclosed by the curve y = x2 + 2x + 3 and the lines x = 1
and x = 0.

Answer 1

Объяснение:

$y=x^2+2x+3\ \ \ \ x=0\ \ \ \ x=1\ \ \ \ S=?\\S=\int\limits^1_0 {(x^2+2x+3)} \, dx= (\frac{x^3}{3} +x^2+3x)\ |_0^1=\frac{1^3}{3}+1^2+3*1-(\frac{0^3}{3}+0^2+3*0)=\\=\frac{1}{3} +1+3-0=4\frac{1}{3}.$

Ответ: S=4,3333 кв.ед.