Question

СРОЧНЕЕ НЕКУДА! ДАЮ 50 баллов!

1. Раскройте скобки
2. Сократите дробь

Answer 1

$\bf\displaystyle\star\ (a+b)^2=a^2+2ab+b^2\ \star\\\\1.\ \Big(a+\dfrac{x}{2}\Big)^2=a^2+2a\cdot\dfrac{x}{2}+\Big(\dfrac{x}{2}\Big)^2=a^2+ax+\dfrac{x^2}{4}\\\\\\\displaystyle2.\ \dfrac{2k^3-8zk^2}{3kz-12z^2}=\dfrac{2k^3-8k^2z}{3z(k-4z)}=\dfrac{2k^2(k-4z)}{3z(k-4z)}=\dfrac{2k^2}{3z}$

Answer 2

$1)(\big{a}+\frac{\big{x}}{\big{2}}) ^2=\big{a^2} +2*a*\frac{\big{x}}{\big{2}}+(\frac{\big{x}}{\big{2}})^2=\boxed{a^2+ax+\frac{\big{x^2}}{\big{4}}}\\\\2)\frac{\big{2k^3-8zk^2}}{\big{3kz-12z^2}}=\frac{\big{2k^2(k-4z)}}{\big{3z(k-4z)}}=\boxed{\frac{\big{2k^2}}{\big{3z}}}$