Question

Помогите решить .......................................

Answer 1

Ответ:

$a)\ \ \displaystyle \int\limits^4_1\, \Big(2x+\frac{3}{\sqrt{x} }\Big)\, dx=\Big(x^2+6\sqrt{x}\Big)\Big|_1^4=(16+12)-(1+6)=21\\\\\\b)\ \ \int\limits^9_4\Big(6-\frac{5}{\sqrt{x} }\Big)\, dx=\Big(6x-10\sqrt{x}\Big)\Big|_4^9=(54-30)-(24-20)=20$