Question

Помогите решить$\frac{x^{2} }{4} +\frac{x}{9}=1\frac{2}{9}$

Answer 1

$\dfrac{x^{2} }{4}+\dfrac{x}{9}=1\dfrac{2}{9} \\\\\dfrac{x^{2} }{4}+\dfrac{x}{9}-\dfrac{11}{9}=0\\\\\dfrac{x^{2} }{4}\cdot 36+\dfrac{x}{9}\cdot 36-\dfrac{11}{9}\cdot 36=0\\\\9x^{2}+4x-44=0\\\\D=4^{2} -4\cdot 9\cdot (-44)=16+1584=1600=40^{2}\\\\x_{1}=\dfrac{-4-40}{18}=-2\dfrac{4}{9}\\\\x_{2} =\dfrac{-4+40}{18}=2\\\\Otvet:\boxed{-2\dfrac{4}{9} \ ; \ 2}$